I found a website that help promotes logical thinking , there will be a period of competition , you can register get start for the competition and get points , Let's take a look at recent matches .
A - November 30
Solution
2019-M2-D2 follows 2019-M1-D1 so we just check M1 & M2 are they equal
m1, d1 = map(int, input().split()) m2, d2 = map(int, input().split()) if m1 == m2: print(0) else: print(1)
B - Tax Rate
Solution
this question the point is rounded down to the nearest integer , math.ceil(N / 1.08) is before tax , round down math.ceil(N / 1.08) times 1.08 to an integer if result equal N Takahashi's memory is true print(result) else false print(":(")
import math
N = int(input())
B = math.ceil(N / 1.08)
if math.floor(B * 1.08) == N:
print(B)
else:
print(':(')
C - 100 to 105
Solution
if one items cost range is 100~105 , two items is 200 ~210 , three items is 300~315 , and so on ,
each item plus 5 tens digit , so we can get the rules
each item plus 5 tens digit , so we can get the rules
x = int(input())
count = x//100
res = x%100
if count*5 >= res:
print(1)
else:
print(0)
D - Lucky PIN
Solution
Use three loops to get three unique values. Loops meet the condition index value +1 to find the value of the next position
N = int(input())
S = input()
cnt = 0
for i in range(10):
for j in range(10):
for k in range(10):
idx = S.find(str(k))
if idx != -1:
idx = S.find(str(j),idx+1)
if idx != -1:
idx = S.find(str(i),idx+1)
if idx != -1:
cnt += 1
print(k,j,i)
print(cnt)
to be continued....
